How fast is the watermelon going when it passes Superman?

As a science project, you drop a watermelon off the top of the Empire State Building, 320 m above the sidewalk. It so happens that Superman flies by at the instant you release the watermelon. Superman is headed straight down with a speed of 35.0m/s .|||Distance for watermelon, d = 1/2 . g . t^2





Distance for Super man d = v . t





These distance are the same, so





vt = 1/2 g t^2





70 /9.8 = t = 7.14 s ( this is the time when they are the same place.)





Speed of the watermelon at this time





v = 9.8 . 7.14 = 70 m/s





Which makes sense....... his constant speed is 35 m/s, so you want the watermelon to have an average speed of 35 m/s. Starting from zero, its final speed has to be 70 m/s in order to get the average of 35........ No other working needed !|||Was this before or after he tricked the drunk into jumping out of the building?





Also how much booze did super-drunk have?





Seriously what about the cross section of the water melon? This will affect its terminal velocity, due to the resistance of the air to its passage.





Also how fast was superman flying, or was he just letting himself fall to make a big hole?





At what height did his path intersect that of the falling watermelon?|||Hi, I'm Kdawg, and I am determined not to learn physics.