Wednesday, September 14, 2011

What horizontal force must Superman apply to the boulder to give it a horizontal acceleration of 14.8 m/s^2?

Superman throws a boulder of weight 3300N at an adversary.|||F=ma


m= mass= 3300 N/g = 336.4 kg


g= gravity = 9.81 m/s^2


a= 14.8 m/s^2


F= 4984 N|||F=MA


48840|||So we鈥檙e supposed to just do your homework for you, you cheating lazy person?!!|||Fs= 3300 i + (3300/9.8)*14.8 j


= 3300 i + 4530 j N





Are you taking PHY 131 at Stony by professor Michael Rijssenbeek??

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